corejava-string-handling: Arrange the words as letter chain

Better and safe approach is instead of while loop just use for loop and it´ll give the output at least one word if there is no word starts with the trailing letter of first word.

import java.util.Scanner;

public class ReorderSentence {
public static void main(String[] args) {
Scanner input=new Scanner(System.in);
String sentence=input.nextLine();
String[] words=sentence.split(" ");
StringBuilder formattedString=new StringBuilder(words[0]);
for(int j=1;j<words.length;j++){
for(int i=1;i<words.length;i++){
if(formattedString.toString().endsWith(Character.toString(words[i].charAt(0)))){
formattedString.append(" "+words[i]);
}
}
}
System.out.println(formattedString.toString());
}
}

import java.util.Scanner;

public class ReorderSentence {
public static void main(String[] args) {
Scanner input=new Scanner(System.in);
String sentence=input.nextLine();
String[] words=sentence.split(" ");
StringBuilder formattedString=new StringBuilder(words[0]);
while(formattedString.toString().length()!=sentence.length()){
for(int i=1;i<words.length;i++){
if(formattedString.toString().endsWith(Character.toString(words[i].charAt(0)))){
formattedString.append(" "+words[i]);
}
}
}
System.out.println(formattedString.toString());
}
}