corejava-programming: Please give program for printing following pattern

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corejava x 353
programming x 169
Posted On : 2016-09-06 10:59:28.0

Answers

public class Pattern {
public static void main(String[] args) {
int count=3;
for(int i=1;i<=6;i++){
for(int j=1;j<=count;j++){
System.out.print("*");
}
if((count==1 || count==2) && i<=3){
count=2*count;
}
if(count==3){
count=1;
}
if(count==4 && i==4){
count=count/2;
}
if(count==2 && i==5){
count=count*3;
}
System.out.println("");
}
}
}

Posted On : 2016-09-06 14:07:40
Satisfied : 1 Yes 0 No

Rishi Kumar
523188249150
Reply This Thread

-2

can we do like this ?

int b=3,a=1;
for (int i = 1; i < 4; i++)
{
for (int j = 1; j <= b; j++) {
System.out.print("*");
}
System.out.println();
for (int j1 = 1; j1 <= a; j1++)
{
System.out.print("*");
}
System.out.println();

int c=0;

if(b>a)
c=b-a;
else
c=a-b;

a=a+b;
b=c;

}

Posted On : 2016-09-06 15:44:18
Satisfied : 1 Yes 0 No

rahul patil
42-30
Reply This Thread

-3

Comments

We can solve one problem by multiple ways, but what matters is how much resource we consume. I want to make some changes in first answer posted by Raj.

int count=3;
for(int i=1;i<=6;i++){
for(int j=1;j<=count;j++){
System.out.print("*");
}
if(count==3){
count=1;
}
else if((count==1 || count==2) && i<=3){
count=2*count;
}
else if(count==4 && i==4){
count=count/2;
}
else if(count==2 && i==5){
count=count*3;
}
System.out.println("");
}

Garima Gupta
596 1295 58962 Posted On :2016-09-06 16:16:24.0
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